The difference of the two roots of a quadratic equation is 5 and the difference of the square of the two roots is 85. Write the quadratic equation in general form.
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Answered by
2
Answer:
Explanation:
Sol. Let α and β be the roots of a quadratic equation.
∴ α - β = 5 [Given] ...... eq. (1)
and α3 - β3 = 215 ............ eq. (2)
We know that,
α3 - β3 = (α - β )3 + 3αβ (α - β )
∴ 215 = 53 + 3αβ (5) [ From eq. (1) & (2)]
∴ 215 – 125 = 15αβ
∴ 90 = 15αβ
∴ α β = 90/15
∴ α β = 6
Also, (α - β )2 = (α + β )2 – 4αβ
∴ 52 = (α + β )2 – 4(6)
∴ 25 + 24 = (α + β )2
∴ (α + β )2 = 49
∴ α + β = ± √49
∴ α + β = ± 7
We know that, Quadratic equation is given by,
x2 – (Sum of the roots)x + Product of the roots = 0
∴ x2 –( α + β)x + αβ = 0
∴ x2 – (±7)x + (6) = 0
∴ x2 ±7x +6 = 0
hope it is helpful...
Answered by
1
Let X and Y be two roots of equation.
A/Q,
X - Y = 5 ………(1)
while,
X^2 - Y^2 = 85
(X - Y)(X + Y) = 85
X + Y = 17………(2)
Solving 1 and 2,
We get X= 11 and Y = 6
The equation is :
x^2 -(X+Y)x +XY
i.e. x^2 - 17x +66 = 0
A/Q,
X - Y = 5 ………(1)
while,
X^2 - Y^2 = 85
(X - Y)(X + Y) = 85
X + Y = 17………(2)
Solving 1 and 2,
We get X= 11 and Y = 6
The equation is :
x^2 -(X+Y)x +XY
i.e. x^2 - 17x +66 = 0
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