The difference of twice the smaller of the two consecutive integers and the larger is 39. Find the
integers and check your answer.
Answers
Answered by
1
Answer:
Step-by-step explanation:
Let the smaller integer be X therefore the larger integer = X + 1.
According to question,
( X + 1 )- 2 X = 39
X -2 X= 39 - 1
-X=38.
Therefore X = -38.
X + 1= -38 + 1 = -37.
Verification:
L. H. S.
=-37 - (2 × -38)
=-37 + 76
=39
= R. H. S.
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Answered by
1
Let the three numbers be: x-1, x and x+1.
-Therefore, x-1 + x + x+1 =3x = 39
-Hence x, the middle number is 13.
-The other two numbers are 12 and 14.
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