Math, asked by aadisingh07, 8 months ago

the difference of twice the smaller of the two consecutive integers and the larger is 39,find the integers and check your answer।​

Answers

Answered by Pragyanshree
3

Answer:

2s - b = 39

b - s = 1

b = 1 + s

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2s - (1 + s) = 39

s - 1 = 39

Answer:

s = 40

b = 41

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