Question

the difference of twice the smaller of the two consecutive integer and the larger is 39 . find the integer ​

Answer 1

To find:

Two consecutive integers where twice the difference between the smallest integer and the larger of the two consecutive integer is 39.

Answer:

The integers are 38 and 39.

Step-by-step explanation:

Let the two consecutive integers be x and x+1;

 Given:

    Difference of twice the smaller of two consecutive integers is 39.

  Therefore 2x-x+1=39.

           x+1=39.

           x=38.

Therefore the two consecutive integers are 38 and 39 where the difference of twice the smaller number that is 38 and the larger one is 39.

Answer 2

Let the three numbers be: x-1, x and x+1.

-Therefore, x-1 + x + x+1 =3x = 39

-Hence x, the middle number is 13.

-The other two numbers are 12 and 14.