Question

the difference of two integers is 3 and the product is 40. find the two integers

Answer 1

$\huge \bigstar \mathfrak \blue {Qᴜᴇsᴛɪᴏɴ}$

ᴛʜᴇ ᴅɪғғᴇʀᴇɴᴄᴇ ᴏғ ᴛᴡᴏ ɪɴᴛᴇɢʀʀs ɪs 3 ᴀɴᴅ ᴛʜᴇ ᴘʀᴏᴅᴜᴄᴛ ɪs 40. ғɪɴᴅ ᴛʜᴇ ᴛᴡᴏ ɪɴᴛᴇɢᴇʀs.

$\huge \bigstar \mathfrak \red {ᴀɴsᴡᴇʀ}$

ғɪɴᴅ -:

• Find the two integers.

$\huge \boxed {Solution}$

If a and b are the numbers, a-b=3, so b=a-3, and ab=40, so a(a-3)=40. a^2-3a-40=0 factorises: (a+5)(a-8)=0. a=-5 or 8, making b=-8 or 5. The two numbers are -5 and -8, or 5 and 8.

Answer 2

Answer:

★Qᴜᴇsᴛɪᴏɴ

ᴛʜᴇ ᴅɪғғᴇʀᴇɴᴄᴇ ᴏғ ᴛᴡᴏ ɪɴᴛᴇɢʀʀs ɪs 3 ᴀɴᴅ ᴛʜᴇ ᴘʀᴏᴅᴜᴄᴛ ɪs 40. ғɪɴᴅ ᴛʜᴇ ᴛᴡᴏ ɪɴᴛᴇɢᴇʀs.

\huge \bigstar \mathfrak \red {ᴀɴsᴡᴇʀ}★ᴀɴsᴡᴇʀ

ғɪɴᴅ -:

Find the two integers.

\huge \boxed {Solution}

Solution

If a and b are the numbers, a-b=3, so b=a-3, and ab=40, so a(a-3)=40. a^2-3a-40=0 factorises: (a+5)(a-8)=0. a=-5 or 8, making b=-8 or 5. The two numbers are -5 and -8, or 5 and 8.