Question

The difference of two natural no is 3 and difference of their reciprocala is 3/28 find thw no

Answer 1

Answer:

x - y = 3

1/x - 1/y = 3/28

1/y - 1/x = - 3/28

(x - y) /x*y = - 3/28

3/xy = - 3/28

xy = - 28

(x + y) ^2 = (x - y) ^2 + 4xy = 9 - 112 = - 103

x + y = +i*sqrt(103), - i*sqrt(103)

x = 1.5 +/- 0.5i*sqrt(103)

y = - 1.5 +/- 0.5i*sqrt(103)

solved