The difference of two natural no. is 5..and the differences of their reciprocal is 5÷14.find the number.
Answers
Let the two natural numbers be x and y.
A/q
y - x = 5
1/x - 1/y = 5/14
From 1.
y = x + 5
Putting the value of y in eqn. 2
1/x - 1/(x+5) = 5/14
x+5-x / x(x+5) = 5/14
5 / x2 + 5x = 5/14
x2 + 5x - 14 = 0
x2 + (7-2)x - 14 = 0
x2 + 7x - 2x - 14 = 0
x(x+7) - 2(x+7) = 0
(x+7) (x-2) = 0
Either
x+7 = 0
x = -7
Not acceptable because -7 is not a natural number.
Or,
x - 2 = 0
x = 2
so,First number = 2
Other number = (x+5)
2 + 5 = 7
Answer:
Step-by-step explanation:
Let the two natural numbers be x and y.
A/q
y - x = 5
1/x - 1/y = 5/14
From 1.
y = x + 5
Putting the value of y in eqn. 2
1/x - 1/(x+5) = 5/14
x+5-x / x(x+5) = 5/14
5 / x2 + 5x = 5/14
x2 + 5x - 14 = 0
x2 + (7-2)x - 14 = 0
x2 + 7x - 2x - 14 = 0
x(x+7) - 2(x+7) = 0
(x+7) (x-2) = 0
Either
x+7 = 0
x = -7
Not acceptable because -7 is not a natural number.
Or,
x - 2 = 0
x = 2
so,First number = 2
Other number = (x+5)
2 + 5=7
HOPE IT HELPS U N PLZ MARK ME AS BRAINLIEST