Math, asked by Abhi5369, 1 year ago

The difference of two natural number is 5 and the difference of their reciprocals is 1/10 find the numbers.

Answers

Answered by Jehan
5
let the first natural no be x

second will be y

then ac to artist
x-y =5____--_______(1)


and again 1/x-1/y=1/10_________2)

x-y/x●y=1/10
xy=5
now,
x-y=50___-_(1)

x+y=√(x-y)^2+4xy
x+y=5^2+50*4

x+y=√225_---;--;----(3)
x+y=+-15
from 1 and 3 each other.

x-y=5
x+y=-15 if it is negative
_____
2x=10
x=5
and y=10

and.if it is -15
then
x-y=5
x+y=15
_____
2x=20
x=10
and y=5ans

hope it help you 


pls mark as brainliest


Abhi5369: hi i think your answer is wrong because 1/10-1/5not equal to 1/10
Answered by 2veer2
2
let two no be x and y, then
x - y = 5 \\ and  \:  \frac{1}{x}  -  \frac{1}{y}  =  \frac{1}{10} \\ put \: x = 5 + y \: in \: second \: eq \: n \: solve \: it
Similar questions