The difference of two natural number is180 .The squareof the smaller number is 8 times the larger number. Find the two number
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let the 2 number be x the largest & y the smallest.
x^2 - y^2 = 180...........(equ.1)
y^2 = 8x
x^2 - 8x -180 = 0
x^2 -18x + 10x -180 = 0
x(x-18) + 10(x-18) = 0
(x-18)(x+10)= 0
x =18 , x = -10 (Not in negative)
so y^2 = 8x
y =√8x
y =√(8×18)
y =√144
y = 12
so the x and y are 18 & 12 respectively
Pls MARK IT AS BRAINLIEST
x^2 - y^2 = 180...........(equ.1)
y^2 = 8x
x^2 - 8x -180 = 0
x^2 -18x + 10x -180 = 0
x(x-18) + 10(x-18) = 0
(x-18)(x+10)= 0
x =18 , x = -10 (Not in negative)
so y^2 = 8x
y =√8x
y =√(8×18)
y =√144
y = 12
so the x and y are 18 & 12 respectively
Pls MARK IT AS BRAINLIEST
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