The difference of two natural numbers is 5 and the difference of their reciprocals is 1/10. Find the numbers
Answers
Answered by
4
according to question let first no x
second be y
so in first situation
x-y=5
x=5+y. (1)
in second equation
1/x-1/y=1/10
by putting values of (1)
1/5+y-1/y=1/10
so equation form and answer
y=5
and
x=10
second be y
so in first situation
x-y=5
x=5+y. (1)
in second equation
1/x-1/y=1/10
by putting values of (1)
1/5+y-1/y=1/10
so equation form and answer
y=5
and
x=10
nims4ever:
can you please tell me the equation that is formed
Answered by
0
Let the first natural no be x
second will be y
then ac to artist
x-y =5____--_______(1)
and again 1/x-1/y=1/10_________2)
x-y/x●y=1/10
xy=5
now,
x-y=50___-_(1)
x+y=√(x-y)^2+4xy
x+y=5^2+50*4
x+y=√225_---;--;----(3)
x+y=+-15
from 1 and 3 each other.
x-y=5
x+y=-15 if it is negative
_____
2x=10
x=5
and y=10
and.if it is -15
then
x-y=5
x+y=15
_____
2x=20
x=10
and y=5ans
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