Question

the difference of two natural numbers is 5 and the difference of their reciprocals is 1/10. find the numbers

Answer 1

x-y=5 - (1)
1/X-1/Y=1/10 -(2)
SO by eqn 1 we get d value of x=5+y nd by putting the value of x in eqn (2) we will get the two no........that is x=-10 nd y=5
......hope it's helpful to uhh!
......by Preity mishra

Answer 2

Let the first natural no be x

second will be y

then ac to artist

x-y =5____--_______(1)

and again 1/x-1/y=1/10_________2)

x-y/x●y=1/10

xy=5

now,

x-y=50___-_(1)

x+y=√(x-y)^2+4xy

x+y=5^2+50*4

x+y=√225_---;--;----(3)

x+y=+-15

from 1 and 3 each other.

x-y=5

x+y=-15 if it is negative

_____

2x=10

x=5

and y=10

and.if it is -15

then

x-y=5

x+y=15

_____

2x=20

x=10

and y=5ans