Question

The difference of two no. is 72 and the quotient obtained by dividing one by other is 3.find the no. ​

Answer 1

$\huge\mathfrak{Answer:}$

Given:

• We have been given that the difference of two numbers is 72.
• The quotient obtained by dividing one by other is 3.

To Find:

• We need to find the number.

Solution:

Let the first number be x.

=> Second number is x + 72

According to the question, we have

$\mapsto\sf{ \dfrac{(x + 72)}{x} = 3}$

On cross multiplying the terms, we have

$\longrightarrow\sf{ x + 72 = 3x}$

$\implies\sf{72 = 3x - x}$

$\implies\sf{72 = 2x}$

$\implies\sf{x = \dfrac{72}{2}}$

$\implies\sf{x = 36}$

Therefore, one number is 36 and other number (x + 72) = (36 + 72) = 108.

Verification:

$\longrightarrow\sf{108 - 36}$

$\sf{ = 72}$

Hence verified!!

Answer 2

Step-by-step explanation:

Given :-

• The difference of two no. is 72

• The quotient obtained by dividing one by other is 3.

To Find :-

• Find the no.

supposed the number is x and y.

• x - y =72.......equation.1
• x = 3y .......equation.2

• putting equestion2 value from equation1

=> x - y = 72

=> 3y - y =72

=> 2y =72

=> y =36

• putting value in from equ.2

=> x - y =72

=> x - 36 =72

=> x = 72+36

=> x = 108

Hence Answer is x= 108 , y =36