The difference of two number is 14 their lcm and hcf are 441 and 7 find the numbers
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we know that product of LCM and hcf of two numbers is equal to their individual product therefore if we let the numbers as a and b thus , ab=441×7
and a-b=14 (taking a as bigger among two number)
=a=14+b
now,
b(14+b)=441×7
we will get a quadratic eq
b^2+14b-441×7=0
by solving it we will get the value of b
=49
there a=63
hope u like it.
and a-b=14 (taking a as bigger among two number)
=a=14+b
now,
b(14+b)=441×7
we will get a quadratic eq
b^2+14b-441×7=0
by solving it we will get the value of b
=49
there a=63
hope u like it.
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