Question

the difference of two number is 20% of the large number. if the smaller is 12 , the large one is

Answer 1

Let the large number be x

Let the large number be xand the smaller number be y that is 12

Let the large number be xand the smaller number be y that is 12x-12=20/100 of x

Let the large number be xand the smaller number be y that is 12x-12=20/100 of x

Let the large number be xand the smaller number be y that is 12x-12=20/100 of x x-12=x/5 , multiplying both sides by 5

Let the large number be xand the smaller number be y that is 12x-12=20/100 of x x-12=x/5 , multiplying both sides by 55x-60=x

Let the large number be xand the smaller number be y that is 12x-12=20/100 of x x-12=x/5 , multiplying both sides by 55x-60=x5x-x=60

Let the large number be xand the smaller number be y that is 12x-12=20/100 of x x-12=x/5 , multiplying both sides by 55x-60=x5x-x=604x=60

Let the large number be xand the smaller number be y that is 12x-12=20/100 of x x-12=x/5 , multiplying both sides by 55x-60=x5x-x=604x=60x=60/4

Let the large number be xand the smaller number be y that is 12x-12=20/100 of x x-12=x/5 , multiplying both sides by 55x-60=x5x-x=604x=60x=60/4x=15

Let the large number be xand the smaller number be y that is 12x-12=20/100 of x x-12=x/5 , multiplying both sides by 55x-60=x5x-x=604x=60x=60/4x=15Therefore the larger number is 15

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