Question

the difference of two number is 3 and the difference in their square is 69 find the number

Answer 1

Hi ,

Let x and y are two numbers,

x - y = 3 ------( 1 )

x² - y² = 69

( x + y ) ( x - y ) = 69

( x + y ) × 3 = 69

x + y = 69 / 3

x + y = 23 ---( 2 )

add equations ( 1 ) and ( 2 ) , we get

2x = 26

x = 26/2

x = 13

put x = 13 in equation ( 2 ) , we get

13 + y = 23

y = 23 - 13

y = 10

Therefore ,

x = 13

y = 10

I hope this helps you.

:)

Answer 2

Step-by-step explanation:

Let the Two Numbers be A and B

Given : The Difference of Two Numbers is 3

⇒ A - B = 3

⇒ A = B + 3

Given : The Difference of their Squares is 69

⇒ A² - B² = 69

Substituting A = (B + 3) in the Above Equation, We get :

⇒ (B + 3)² - B² = 69

⇒ B² + 9 + 6B - B² = 69

⇒ 6B = 69 - 9

⇒ 6B = 60

⇒ B = 10

Substituting B = 10 in A = (B + 3), We get :

⇒ A = (10 + 3) = 13

So, The Two Numbers are 10 and 13