the difference of two number is 3 and the difference of their square is 69.find the number
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Answered by
216
Heya user !!!
Here's the answer you are looking for
Let the numbers be x and y
The question says, their difference is 3
So, x - y = 3
x = 3 + y
Now we get the 2 numbers as y and (y+3)
Also, difference of their squares is 69
That is, x² - y² = 69
But x = y+3
So, (y+3)² - y² = 69
y² + 3² + 2(3)(y) - y² = 69
9 + 6y = 69
6y = 69 - 9 = 60
y = 60/6 = 10
x = y + 3 = 10 + 3 = 13
Therefore, the numbers are 10 and 13.
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
Let the numbers be x and y
The question says, their difference is 3
So, x - y = 3
x = 3 + y
Now we get the 2 numbers as y and (y+3)
Also, difference of their squares is 69
That is, x² - y² = 69
But x = y+3
So, (y+3)² - y² = 69
y² + 3² + 2(3)(y) - y² = 69
9 + 6y = 69
6y = 69 - 9 = 60
y = 60/6 = 10
x = y + 3 = 10 + 3 = 13
Therefore, the numbers are 10 and 13.
★★ HOPE THAT HELPS ☺️ ★★
Answered by
9
The numbers are 10 and 13
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