Question

the difference of two number is 4. If the difference of their reciprocal is 4 /21 then, find the two no.

Answer 1

x-y = 4.................eqn 1st
1/y-1/x = 4/21
x-y/xy=4/21
Put the value of x-y
4/xy = 4/21
1/xy = 1/21
xy = 21
x = 21/y
Put the value of x in eqn 1st
-y+21/y = 4
21-y^2 = 4y
y^2+4y-21 = 0
y^2+7y-3y-21=0
y (y+7)-3 (y+7)
(y+7)(y-3)
So the numbers are......
y-3 = 0
y = 3 and
y+7 = 0
y = -7

Answer 2

Answer:

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