Question

the difference of two number x is 18 and half of their sum is 48 find the numbers​

Answer 1

Answer:

Let the numbers be x and y .

★ In the 1st case ,

† Difference between x and y is 18

$\large \bold{→ x - y = 18} \: \: - - (1)$

★ In the 2nd case ,

† Half of sum of x and y is 48

$\large \bold{→ \frac{x + y}{2} = 48}$

$\large \bold{→ {x + y} = 48 \times 2}$

$\large \bold{→ {x + y} = 96} \: \: - - - (2)$

Now,

eq(2) – eq(1) ,

→ ( x + y ) - (x - y) = 96 - 18

→ x + y - x + y = 78

→ 2y = 78

→ y = 78/2

→ $\large\boxed{\bold{y\:=\:39}}$

Putting the value of y in eq(1) , we get

→ x - 39 = 18

→ x = 18 + 39

→ $\large\boxed{\bold{x\:=\:57}}$

Hence , the numbers are 57 and 39 .