Question

The difference of two numbers is 14.their lcm and hcf are 441 and 7.find the numbers?

Answer 1

Answer:

The required numbers are  63 and 49

Step-by-step explanation:

Concept:

Product of two numbers= (HCF)*(LCM)

Let the two numbers be x and y with x>y.

Also x - y=14...............(1)

H.C.F of x and y =7

L.C.M of x and y= 441

Then,

xy=441*7

xy=7*3*7*3*7

xy=63*49.................(2)

From (1) and (2)

x= 63 and y=49

Answer 2

Answer:

49 & 63

Step-by-step explanation:

The difference of two numbers is 14.their lcm and hcf are 441 and 7.find the numbers?

Let say two numbers are

x &  x +  14

LCM & HCF = 441 & 7

Product of numbers = LCM * HCF

=> x (x+14) = 441 * 7

=> x² + 14x = 3087

=> x² + 14x - 3087 = 0

=> x² + 63x - 49x - 3087 = 0

=> x(x+63) -49(x+63) = 0

=> (x-49)(x+63) = 0

x = 49

x + 14 = 63

numbers = 49 & 63