Question

The difference of two numbers is 14. Their LCM and HCF are 441 and 7. Find the two numbers ?​

Answer 1

Answer:

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Step-by-step explanation:

Since their HCFs are 7, numbers are divisible by 7 and are of the form 7x and 7y

Difference = 14

=> 7x - 7y = 14

=> x - y = 2

product of numbers = product of their hcf and lcm

=> 7x * 7y = 441 * 7

=> x * y = 63

Now, we have

x * y = 63 , x - y = 2

=> x = 9 , y = 7

The numbers are 7x and 7y

=> 63 and 49

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