the difference of two numbers is 16 if one number is 3/2 of the Other find the greatest number
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Complete step by step answer:
Let one of the numbers is x and the other is y. Let x > y.
Since the difference of the two number is 16, we have
x−y=16 (i)
Also, since one-third of the smaller number is greater than one-seventh of the larger number by 4, we have
y3−x7=4
Multiplying both sides by 21, we get
7y−3x=84 (ii)
From equation (i), we have
x−y=16⇒x=y+16 (iii)
Substituting the value of x in equation (ii), we get
7y−3(y+16)=84
Using distributive property of multiplication over addition, i.e. a(b+c) = ab+ac, we get
7y−3y−48=84⇒4y−48=84
Dividing both sides by 4, we get
y−12=21
Adding 12 on both sides, we get
y=33
Substituting the value of y in equation (iii), we get
x=y+16=33+16=49
Hence the two numbers are 49 and 33.
Answered by
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Answer:
x-3x/2 = 16
-x/2 = 16
-x = 32
x = -2
x-3x/2 = 16
-x/2 = 16
-x = 32
x = -2
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