Question

the difference of two numbers is 3 and and the difference of their squares is 69. find the numbers

Answer 1

13 and 10
13-10= 3
(13)^2-(10)^2=169-100=69

Here is the proper method
Let the numbers be x and y (x>y)
x-y=3
x2-y2=69
(x-y)(x+y)=69
3(x+y)=69
x+y=23 -eq(1)
x-y=3 -eq(2)
Adding eq(1) and eq(2)
2x=26
x=13
13-y=3
y=10

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