The difference of two numbers is 3 and the difference off the square is 69 find the numbers
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Answered by
2
let the two no.s be x,y
x-y=3 --------------eq 1
x²-y²=69
(x+y)(x-y)=69
x+y=69/3
x+y=23--------------eq 2
x-y=3
__________
2x=26
x=13
in eq 1
x-y=3
13-y=3
y=10
x-y=3 --------------eq 1
x²-y²=69
(x+y)(x-y)=69
x+y=69/3
x+y=23--------------eq 2
x-y=3
__________
2x=26
x=13
in eq 1
x-y=3
13-y=3
y=10
profswh:
did your steps end up at the correct answer
yes they did
y=16 is right
13sq.-10sq=69
13-10=4
who is 16sq-13sq=69 it is wrong
256-169!=69
256-169=87
then look what has the question given dont simply argue
so what do you wanna say
Answered by
1
Step-by-step explanation:
Let the Two Numbers be A and B
Given : The Difference of Two Numbers is 3
⇒ A - B = 3
⇒ A = B + 3
Given : The Difference of their Squares is 69
⇒ A² - B² = 69
Substituting A = (B + 3) in the Above Equation, We get :
⇒ (B + 3)² - B² = 69
⇒ B² + 9 + 6B - B² = 69
⇒ 6B = 69 - 9
⇒ 6B = 60
⇒ B = 10
Substituting B = 10 in A = (B + 3), We get :
⇒ A = (10 + 3) = 13
So, The Two Numbers are 10 and 13
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