The difference of two numbers is 4. If the difference of their reciprocals is 4/21, find the two numbers.
Answers
Answer:
the numbers are 3 and 7
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Answer:
The required numbers are - 3 and - 7.
The required numbers are 7 and 3.
Step-by-step-explanation:
Let the greater number be x.
And the smaller number be y.
From the first condition,
x - y = 4
x = y + 4 - - ( 1 )
From the second condition,
1 / x - 1 / y = 4 / 21
y - x / xy = 4 / 21
21 ( y - x ) = 4xy
21y - 21x = 4xy - - ( 2 )
Now, by substituting the value of x from the equation ( 1 ) in equation ( 2 ), we get,
21y - 21x = 4xy - - ( 2 )
21y - 21 ( y + 4 ) = 4 × ( y + 4 ) × y
21y - 21y - 84 = ( 4y + 16 ) × y
- 84 = 4y² + 16y
4y² + 16y + 84 = 0
y² + 4y + 21 = 0 - - [ Dividing both sides by 4 ]
y² + 7y - 3y + 21 = 0
y ( y + 7 ) - 3 ( y + 7 ) = 0
( y + 7 ) ( y - 3 ) = 0
y + 7 = 0 y - 3 = 0
Now, by substituting y = - 7 in equation ( 1 ), we get,
x = y + 4
x = - 7 + 4
Now, by substituting y = 3 in equation ( 1 ), we get,
x = y + 4
x = 3 + 4
The required numbers are - 3 and - 7.
The required numbers are 7 and 3.