the difference of two numbers is 5 and difference in their reciprocal is 1/10. find the numbers
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a-b=5...1
therefore a=b+5
1/a -1/b= 1/10 ....2
substitute value of a in 2
we get an equation b^2 +5b -50
b= 5, -10
a= 10, -5
therefore a=b+5
1/a -1/b= 1/10 ....2
substitute value of a in 2
we get an equation b^2 +5b -50
b= 5, -10
a= 10, -5
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