Question

The difference of two numbers is 5 and the difference of their squares is 135. The sum of the numbers is: select one: a. 32 b. 27 c. 25 d. 30

Answer 1

Answer:

let the numbers be a and b

A-B=5

A²-B²=135

(A-B)(A+B)=A²-B²

5(A+B)=135

(A+B)=135/5

A+B=27

SUM OF THE NUMBERS IS 27

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Answer 2

Concept Introduction:

A prime number is a number that contains exactly two factors, namely $'1'$ and the number itself. Composite numbers can also be divided by at least one positive integer. Apart from being divided by $1$ as well as the actual number, it can also be divided by at least one positive integer.

Given:

The difference of two numbers is $5$ and the difference of their squares is $135$.

Find: We have to the sum of the numbers.

Solution:

According to the problem:

Let the number be a and b.

Then,$(a + b) = (a2 -b2) / (a-b)$

= $135/5$

= $27$

Hence the The sum of the numbers is  $27$.

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