Question

The difference of two squares of (x+y+2z)(x+y)

Answer 1

$(x + y + 2z) {}^{2} - (x + y) {}^{2} \\ = ((x + y) + 2z){}^{2} - (x + y) {}^{2} \\ = ((x + y) {}^{2} + 4 {z}^{2} + 4(x + y)z) - (x + y) {}^{2} \\ = 4 {z}^{2} + 4z(x + y) \\ = 4z(z + x + y)$

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