The difference of two supplementary angles is 40^0, find the angles.
Muthu2004:
i think in this question , the difference of two is 40⁰
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the 2 supplementary angle be x,y
x+y=180⁰ -1
x-y=40⁰ -2
By elimination method of 1 and 2
x+y=180
x-y=40
⁻⁻⁻⁻⁻⁻⁻⁻
2x = 220
x = 220/2 = 110
Substitute x=110 in 1
x+y=180
110+y=180
y=180-110 = 70
the angles are 110⁰ and 70⁰
NOTE : ⁰ HERE IT IS A DEGREE
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