The differencial equation representing the SHM of a particle is (9×d^2Y/dt^2)+4Y=0. The time period of the particle is given by:
a)π/3 sec
b)π sec
c)2π/3 sec
d)3π sec
Answers
Answered by
5
answer : option (d) 3π sec
It has given that the differential equation representing the simple harmonic motion of a particle is (9 d²y/dt² ) + 4y = 0
we have to find the time period of the particle.
here, 9 d²y/dt² +4y = 0
⇒d²y/dt² = -(4/9)y
we know, for simple harmonic motion d²y/dt² = -ω²y
so, ω² = 4/9
⇒ω = 2/3
⇒2π/T = 2/3
⇒T = 3π
therefore time period of the particle is 3π sec.
also read similar questions : A particle executing SHM maximum speed of 30 cm/s and a maximum acceleration of 60 cm/s². The period of oscillation is(a...
https://brainly.in/question/8113407
Distance of a particle undergoing shm in one time period is
https://brainly.in/question/13734724
Similar questions