Math, asked by ankitmishra58, 9 months ago

The different between the ages of two cousins 10 years. 15 years ago, if the elder one was the twice ase old as the younger one, find their present ages. ​

Answers

Answered by Anonymous
2

Answer:

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Answered by izardarvinita123
1

Answer:

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Step-by-step explanation:

let the present agebe x and 2 nd age = x+10

15 years ago

(x-15)*2 = (x+10-15)

2x-30 = x-5

2x-x=30-5

x=25 years

x+10=35years

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