Math, asked by kasaudhanamar0000, 2 months ago

The differential equation (x+y+2)dy/dx+x(x+y-1)=0 is
(A) variable seprable
(B) linear
(C) homogeneous
(D) exact​

Answers

Answered by pulakmath007
7

SOLUTION

TO CHOOSE THE CORRECT OPTION

The differential equation

 \displaystyle \sf{(x + y + 2) \frac{dy}{dx}  + (x + y - 1) = 0}

(A) variable separable

(B) linear

(C) homogeneous

(D) exact

EVALUATION

Here the given differential equation is

 \displaystyle \sf{(x + y + 2) \frac{dy}{dx}  + (x + y - 1) = 0}

Which can be rewritten as

 \displaystyle \sf{(x + y + 2) dy  + (x + y - 1) dx= 0}

 \displaystyle \sf{ \implies \: (x + y - 1) dx +  (x + y + 2) dy = 0}

Which is of the form Mdx + Ndy = 0

Where

M = x + y - 1

N = x + y + 2

Now

 \displaystyle \sf{ \frac{ \partial M }{ \partial y}  = 1}

 \displaystyle \sf{ \frac{ \partial N }{ \partial x}  = 1}

Therefore

 \displaystyle \sf{ \frac{ \partial M }{ \partial y}  =  \frac{ \partial N }{ \partial x}}

So the given differential equation is exact

FINAL ANSWER

Hence the correct option is (D) exact

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