The differential rate law for the reaction
H₂ (g) + I₂ (g) → 2HI (g) is
(a) - d[H₂]/dt = - d[I₂]/dt = - d[HI ]/dt
(b) d[H₂]/dt = d[I₂]/dt = 1/2 d[HI ]/dt
(c) 1/2 d[H₂]/dt = 1/2 d[I₂]/dt = - d[HI ]/dt
(d) -2 d[H₂]/dt = -2 d[I₂]/dt = d[HI ]/dt
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(c ) is right answers
And thank and thank for the point
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Let us answer it
Explanation:
Rate of reaction is actually : time taken for reactants to form products" .
The rate can also be defined as : increase in concentration of products with time
or
decrease in concentration of reactants with time .
For example : we have a reaction
A + B ----> AB
R = -d{AB }dt=d{A }/dt= d{B }/dt
If moles are present then :
aA + bB ---->x AB
Then the expression becomes :
R = -1/x d{AB }/dt=1/a d{A }/dt = -1/b d{B }/dt
Here negative sign indicates = decrease in concentration of reactants .
Here positive sign indicates : increase in concentration of products .
Now in the above asked question : option a is correct .
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