Question

the differenve bw the sides at right angles in a right trianlge is14 cm , the area is120cm. calculate thr perimeter

Answer 1

Answer:

Step-by-step explanation:

let the two sides be : b and h

so according to the ques

b-h = 14

h=14+b 《1》

now we know that

area =1/2 X bXh

put h=14+b

so by putting in formula we will obtain an equation that is

b^2 +14b = 240

b^2 +14b-240=0

by solving with elimination we will

get b=-24 andb=10

as base cant be negative so

b=10

hence

h=24 (by putting in 《1》)

now apply pythagoras and we will get the value of hypotenuse

hyp=26

hence perimeter = b +h+hyp

=10 +24+26

=60