Question

The differnce of two no. no. is 33. If the two no. are in the ratio5:2 then find the no.

Answer 1

Given:-

• Difference between the two numbers is 33.
• The two numbers are in the ratio of 5:2.

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To find:-

• Find the two numbers.

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Solution:-

Let,

• the first number be 5x.
• the second number be 2x.

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According to the question

→ 5x - 2x = 33

→ 3x = 33

→ x = 33/3

→ x = 11

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Therefore,

• First number = 5x = 5 × 11 = 55
• Second number = 2x = 2 × 11 = 22

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Hence,

• the first number is 55 and the second number is 22.

Answer 2

${\underline{\underline{\bf{Given:}}}}$

• The difference of two numbers is 33.
• And the ratio of the same two numbers is 5 : 2.

${\underline{\underline{\bf{Need\:to\:find:}}}}$

• The two numbers.

${\underline{\underline{\bf{Solution:}}}}$

Let, the first number be 5x and the second number be 2x.

According to the question,

$\implies{\sf{5x-2x=33}}$

$\implies{\sf{3x=33}}$

$\implies{\sf{x=\Large{\frac{\cancel{33}}{\cancel{3}}}}}$

$\implies{\underline{\underline{\sf{x=11}}}}$

Now, we know the value of 'x'. So, we can find the two numbers by substituting the value of 'x' in the expression formed for the numbers.

• First number$\rightarrow{\sf{5x=5\times11=\red{\underline{\underline{55}}}}}$
• Second number$\rightarrow{\sf{2x=2\times11=\red{\underline{\underline{22}}}}}$

${\underline{\underline{\bf{Verification:}}}}$

$\rightarrow{\sf{{1}^{st}\:number-{2}^{nd}\:number=33}}$

$\rightarrow{\sf{55-22=33}}$

$\rightarrow{\sf{33=33}}$

$\rightarrow{\sf{L.H.S.=R.H.S.}}$

$\rightarrow{\sf{Hence,\:the\:answer\:is\: correct!}}$

${\underline{\underline{\bf{Required\:answer:}}}}$

• The two numbers are 55 and 22.

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