the diffidence of two numbers is 2 and there product is 120
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let the first number be x
then the other no will be 2-x
according to question
(x) (2-x) =120
2x-x^2=120
2x-120=x^2
x^2-2x+120=0
x^2-40x+30x+120=0
x(x-40) -30(x-40)
(x-30) (x-40)
x=30 or x=40
then the other no will be 2-x
according to question
(x) (2-x) =120
2x-x^2=120
2x-120=x^2
x^2-2x+120=0
x^2-40x+30x+120=0
x(x-40) -30(x-40)
(x-30) (x-40)
x=30 or x=40
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