The diffrence between a 2 digit number and the number obtained by intrrchanging its digits is 63 . What is the diffrence between the digits of the number
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Let ten's digit be x and unit's digit be y.
The sum of digit = x+y
The two digit no. = 10x+y
On reversing the digits , it becomes = 10y+x
According to the question
10x+y-(10y+x)=63
10x+y-10y-x=63
9x-9y=63
9(x-y)=63
x-y=63/9
x-y=7
The difference is 7.
The sum of digit = x+y
The two digit no. = 10x+y
On reversing the digits , it becomes = 10y+x
According to the question
10x+y-(10y+x)=63
10x+y-10y-x=63
9x-9y=63
9(x-y)=63
x-y=63/9
x-y=7
The difference is 7.
iyoman:
thanks
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