Math, asked by neemamehraneema, 4 months ago

The diffrence between ages of two cousins is 10 years. 15 years ago if the eoder one was twice as old as the younger one​

Answers

Answered by ashish79638
3

Answer:

Let the present age be x then 2nd's age x+10

15 yrs ago'

(x-15)*2 = (x+10-15)

2x-30=x-5

2x-x=30-5

x=25

x+10= 35 years

Answered by rupalibhakat66
2

Answer:

35years

Step-by-step explanation:

let the present age be x

let the second age be x+10

15years ago

(x-15)×2=(x+10-15)

2x-30=x-5

2x-x=30-5

x=25years

x+10=35years

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