The diffrence between ages of two cousins is 10 years. 15 years ago if the eoder one was twice as old as the younger one
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Answered by
3
Answer:
Let the present age be x then 2nd's age x+10
15 yrs ago'
(x-15)*2 = (x+10-15)
2x-30=x-5
2x-x=30-5
x=25
x+10= 35 years
Answered by
2
Answer:
35years
Step-by-step explanation:
let the present age be x
let the second age be x+10
15years ago
(x-15)×2=(x+10-15)
2x-30=x-5
2x-x=30-5
x=25years
x+10=35years
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