Math, asked by neemamehraneema, 1 month ago

The diffrence between ages of two cousins is 10 years. 15 years ago if the elder one was twice as old as the younger one​

Answers

Answered by Anonymous
8

Answer:

Let Present age of younger cousin = x

Then age of older cousin ll be = x + 10

15 years ago:

Age of younger cousin = x-15

Age of older cousin = x+10-15 = x-5

According to question,

  • => x-5 = 2(x-15)

  • => x -5 = 2x -30

  • => 2x-x = -5+30

  • => x = 25

So age of younger cousin = 25 years

Age of older cousin = 25+10 = 35 years

Answered by gulabisrinu
2

Answer:

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