The diffrence in age between a girl and her younger sister is 4 years .the younger sister in turn is 4year older than her brother , the sum of the ages of the younger sister and her brother is 16 how old are the three children
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The elder sister is14.The second sister is 10 yes old and the brother is 6yes old
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hi your answer is....
age of the girl = 'x' years.
So, the age of her younger sister = (x - 4) years.
Thus, the age of the brother = (x - 4 - 4) years = (x - 8) years.
According to question:
(x - 4) + (x - 8) = 16
x + x - 4 - 8 = 16
2x - 12 = 16
Adding 12 to both sides, we get
2x - 12 + 12 = 16 + 12
2x = 28
Dividing both sides by 2, we get
2x2 = 282
x = 14
Thus, the age of the girl = x = 14 years, the age of the younger sister = x - 4 = 14 - 4 = 10 years, and the age of the younger brother = x - 8 = 14 - 8 = 6 years.
age of the girl = 'x' years.
So, the age of her younger sister = (x - 4) years.
Thus, the age of the brother = (x - 4 - 4) years = (x - 8) years.
According to question:
(x - 4) + (x - 8) = 16
x + x - 4 - 8 = 16
2x - 12 = 16
Adding 12 to both sides, we get
2x - 12 + 12 = 16 + 12
2x = 28
Dividing both sides by 2, we get
2x2 = 282
x = 14
Thus, the age of the girl = x = 14 years, the age of the younger sister = x - 4 = 14 - 4 = 10 years, and the age of the younger brother = x - 8 = 14 - 8 = 6 years.
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