Question

The diffusion coefficient of an ideal gas is proportional to its mean free path and mean speed. The absolute temperature of an ideal gas is increased 4 times and its pressure is increased 2 times. As a result, the diffusion coefficient of this gas increases x times. The value of x is :

Answer 1

Explanation:

Diffusion Coefficient ∝ λx u avg

λ =1/√ 2π  σ ^2 .N

D.C  ∝ u avg /√ 2π  σ ^2 .N

No = P/KT

u avg ∝ √T

D.C ∝ T^3/2 / P

D.C2/D.C1 = 4*√4 /2

= 8/2

=4