Question

The digit åt tens place of a two digit number is four times the digit at units place. If the
sum of this numbers and the number formed by reversing the digit is 56. Find the
number.​

Answer 1

Correct Question:- The digit at tens place of a two digit number is four times the digit at units place. If the

sum of this numbers and the number formed by reversing the digit is 55. Find the number.

Answer :-

Let the digit at unit place be x and at ten's place by y.

Therefore,the number would be 10 × y + x = 10y + x.

Digit obtained after reversing the digit will be 10x + y as x would be the ten's term now.

Given

• The digit at ten's place is four times the digit at one's place.

• The sum of this numbers and the number formed by reversing the digit is 55.

Therefore, y = 4x

and, ( 10y + x ) + ( 10x + y ) = 55

=> 11x + 11y = 55

Putting y = 4x , we get

=> 11x + 11(4x) = 55

=> 11x + 44x = 55

=> 55x = 55

=> x = 1

Hence, y = 4x = 4

Therefore, x = 1 and y = 4 .

Hence,the number is 10y + x = 10(4) + 1 = 41.

The number is 41.

Answer 2

Answer:

Let's take the number as 10x+y

As per the question,  

y=4x, and  

x+y=10

So, x+4x=10

5x=10

x=2

y=2×4=8

So, the number is 10x+y=10×2+8=28

Step-by-step explanation: I hope it will help u