Question

the digit at ines place of a two digit in 2times the digit in 2 times the digit at ones place if the digit reveresd the new no is formed 18 less than original no find the new original no

Answer 1

Let the digit at one place be x

Digit at tens place=2x

Original no.=10(2x)+x=21x

If the digits are reversed then the new no. Form is=10x+2x=12x

ATQ

21x-12x=18

9x=18

x=18/9=2

Original no.=21x=21*2=42

Reversed no.,=24

And their differences are 42-24=18(verified)