Question

the digit at once palce of a 2 digit number is four times the digit at tens plave the number obtained by reversing the digits exeeds the given number by 54 find the given numbers

Answer 1

here is the answer. plz mark it as brainliest

Answer 2

let the digit in ones place is x.
and the digit in tens place is y.
also x = 4y
so the number is (10y + x)
reversing the digits newly formed number
= (10x + y)
atq,
10x + y - (10y + x) = 54
9x - 9y = 54
9(4y) - 9y = 54
36y - 9y = 54
27y = 54
y = 2
x = 4×2 = 8
so the number is 10(2) + 8 = 28