the digit at once place of a two digit number is 4 times at the digit at tens place the number obtained by reversing the digits exceeds the given number by 54 find the given number
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let ones digit be y
let tens digit be x
x=y/4
10y +x -10x -y=54
40x+x-10x-4x=54
27x=54
therefore the given number is 28
let tens digit be x
x=y/4
10y +x -10x -y=54
40x+x-10x-4x=54
27x=54
therefore the given number is 28
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