Question

the digit at one place of a two digit number is 4 times the digit at tens place is the number obtained by reversing the digits exceeds the given number by 54 find the given number

Answer 1

let the digit at tens place be x&
that of ones be y
y=4x......................(given)
4x-y=0...................(1)
by the first given condition
10y+x=10x+y+54
9y=9x+54
9x-9y=-54
x-y=-6.......(dividing through 9)(2)
subtracting eqn (2) from (1)
3x=6
x=2
substitute x=2 in eq n(2)
y=8
Number:10x+y
=10(2)+(8)
=20+8
=28

Answer 2

Answer:

Step-by-step explanation:

let the digit at tens place be x and

that of ones be y

y=4x......................(given)

4x-y=0...................(1)

by the first given condition

10y+x=10x+y+54

9y=9x+54

9x-9y=-54

x-y=-6.......(dividing through 9)(2)

subtracting eqn (2) from (1)

3x=6

x=2

substitute x=2 in eq n(2)

y=8

Number:10x+y

=10(2)+(8)

=20+8

=28

Thanks you: )