Question

The digit at ones place of a 2-digit number is four times the digit at tens place. The
number obtained by reversing the digits exceeds the given number by 54. Find
the given number.
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Answer 1

Answer:

Let one's digit be 4x. Then, ten's digit =x.

Number =10x+4x=14x ....(1)

Number obtained by reversing the digits =40x+x=41x

According to the given condition,

41x−14x=54

27x=54

x=2

Putting the value of x in (1) , we get

Number =14×2=28

Hence, 28 is the required number

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