Question

the digit at ones place of a 2 digit number is four times the digit at ten place. the number obtained by reversing the digit exceeds the given number by 54 . find the given number .​

Answer 1

$\sf \fbox{ Answer}$

Let the number at one's place be y and ten's place be x.

According to the problem,

y = 4x – (1)

10y + x = 10x + y - 54 – (2)

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Putting the value of y in equation (2)

40x + x = 10x + 4x + 54

= 41x = 14x + 54

= 27x = 54

= x = 2

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Putting the value of x in equation (1)

y = 4(2)

= y = 8

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The required number is:-

10x + y

= 20 + 8

= 28

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