Question

The digit at ones place of a 2 digit number is four times the digit at tens place. The number obtained by reversing the digits exceeds the number 54. Find the given number.

Answer 1

let the digit at tens place be x&

that of ones be y

y=4x......................(given)

4x-y=0...................(1)

by the first given condition

10y+x=10x+y+54

9y=9x+54

9x-9y=-54

x-y=-6.......(dividing through 9)(2)

subtracting eqn (2) from (1)

3x=6

x=2

substitute x=2 in eq n(2)

y=8

Number:10x+y

=10(2)+(8)

=20+8

=28

Answer 2

hope it helps you
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