Question

the digit at ones place of a 2-digit number is four times the digit at tens place .the number obtained by reversing the digits exceeds the given number by 54.find the given number.

Answer 1

Answer:

28

Step-by-step explanation:

let the digit at tens place be x

that of ones be y

y=4x......................(given)

4x-y=0...................(1)

by the first given condition

10y+x=10x+y+54

9y=9x+54

9x-9y=-54

x-y=-6.......(dividing through 9)(2)

subtracting eqn (2) from (1)

3x=6

x=2

substitute x=2 in eq n(2)

y=8

Number: 10x+y

=10(2)+(8)

=20+8

=28

Answer 2

Answer:

28

Step-by-step explanation:

let the digit at tens place be x

that of ones be y

y=4x......................(given)

4x-y=0...................(1)

by the first given condition

10y+x=10x+y+54

9y=9x+54

9x-9y=-54

x-y=-6.......(dividing through 9)(2)

subtracting eqn (2) from (1)

3x=6

x=2

substitute x=2 in eq n(2)

y=8

Number: 10x+y

=10(2)+(8)

=20+8

=28