the digit at ones place of a two digit number is 10. the number obtained by reversing the digit exceeds the given number by 54. find the given number.
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Answered by
1
Hi Mate!!!
Let the be x and y
Any two digit no.s can be written as 10x+y
y = 10. given
According to the question
10x +y = 54 + 10y +x
x - y = 6
x = 16
Have a NYC day.
Let the be x and y
Any two digit no.s can be written as 10x+y
y = 10. given
According to the question
10x +y = 54 + 10y +x
x - y = 6
x = 16
Have a NYC day.
Answered by
3
Hope it helps you Good luck
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